MCQ
$CC{l_4}$ cannot give precipitate with $AgN{O_3}$ due to
- AFormation of complex with $AgN{O_3}$
- BEvolution of $C{l_2}$ gas
- ✓Chloride ion is not formed
- D$AgN{O_3}$ does not give silver ion
Hence it does not give $C{l^ - }$ion in solution.
$CC{l_4} + AgN{O_3} \to {\rm{No}}\,{\rm{reaction}}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$Zn \to Z{n^{2 + }} + 2{e^ - };{E^o} = 0.76\,\,V$,$Fe \to F{e^{2 + }} + 2{e^ - };{E^o} = 0.44\,\,V$ what will be the emf of cell, whose cell-reaction is ............ $\mathrm{V}$
$F{e^{2 + }}(aq) + Zn \to Z{n^{2 + }}(aq) + Fe$
| Column I | Column II |
| (a) Non ideal solution with positive deviation | (i) $H _2 O (57 \%)+ HI (43 \%)$ |
| (b) Maximum boiling azeotrope | (ii) $CHCl _3+\left( CH _3\right)_2 CO$ |
| (c) Non ideal solution with negative deviation | (iii) $C _2 H _5 OH (95.4 \%)+ H _2 O (4.6 \%)$ |
| (d) Minimum boiling azeotrope | (iv) $CCl _4+ C _6 H _5 CH _3$ |