MCQ
$Ce - 58$ is a member of
- A$s$-block elements
- B$p$-block elements
- C$d$-block elements
- ✓$f$-block elements
✓
Answer
Correct option: D.
$f$-block elements
d
The electronic configuration of $Ce$ is $[ Xe ] \,4 f ^1 \,5 d ^1 \,6 s ^2$.
The electronic configuration of $Ce$ is $[ Xe ] \,4 f ^1 \,5 d ^1 \,6 s ^2$.
Since the electron has entered the $f$ orbital, $Ce$ is an $f$ block element.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
True statement for $NO_3^-$ is
→$(a)$ coordination number of $'N'$ is $3$ , and the structure is triagonal planar
$(b)$ formal charge on $N$ is $+1$
$(c)$ Average formal charge on $'O'$ is $-2/3$
$(d)$ Average bond order of $NO$ bond is $4/3$
$(e)$ All $NO$ bond lengths are identical
Correct code is
If $250\, cm ^{3}$ of an aqueous solution containing $0.73\, g$ of a protein $A$ is isotonic with one litre of another aqueous solution containing $1.65\, g$ of a protein $B ,$ at $298\, K ,$ the ratio of the molecular mases of $A$ and $B$ is..........$\times 10^{-2}$ (to the nearest integer).
→When an organic compound was treated with sodium nitrite and hydrochloric acid in the ice cold, nitrogen gas was evolved copiously. The compound is
An alkane has a $C/H-$ ratio (by mass) of $5.1428$. Its molecular formula is
→$KMn{O_4}\xrightarrow[{{{200}^o}C}]{\Delta } 'X' + Mn{O_2} + {O_2}$ Which of the following statement is correct for $'X'$
→Which of the following compounds exhibits optical isomerism
The given reaction is knows as :
Acetaldehyde cannot give:
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,||} \\
{C{H_3} - C - H}
\end{array}$ ${\xrightarrow{{HCN}}(A)\xrightarrow{{{H_3}{O^ \oplus }}}(B)}$ ${\xrightarrow[\Delta ]{{}}(C)\xrightarrow{{LiAl{H_4}}}(D)}$ ${\xrightarrow{{HI{O_4}}}HCHO + (E)}$
→{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,||} \\
{C{H_3} - C - H}
\end{array}$ ${\xrightarrow{{HCN}}(A)\xrightarrow{{{H_3}{O^ \oplus }}}(B)}$ ${\xrightarrow[\Delta ]{{}}(C)\xrightarrow{{LiAl{H_4}}}(D)}$ ${\xrightarrow{{HI{O_4}}}HCHO + (E)}$
Compound $(C)$ can show geometrical isomerism. Product $(E)$ of the reaction will be
Strongest nucleophile in polar protic solvent is