Question
$\ce{[Fe(H_2O)_6]^{3+}}$ is strongly paramagnetic whereas $\ce{[Fe(CN)_6]^{3–}}$ is weakly paramagnetic. Explain.
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Answer
In presence of $CN^–, ($a strong ligand$)$ the $3d$ electrons pair up leaving only one unpaired electron. The hybridisation is $d^2sp^3$ forming inner orbital complex. In the presence of $H_2O, ($a weak ligand$), 3d$ electrons do not pair up. The hybridisation is $sp^3d^2$ forming an outer orbital complex containing five unpaired electrons, thus greater the number of unpaired electrons more is the paramagnetic behavior.
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