$\ce{KMnO_4}$ acts as an oxidising agent in acidic medium. The number of moles of $\ce{KMnO_4}$ that will be needed to react with one mole of sulphide ions in acidic solution is
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$2\text{MnO}_4^-+5\text{S}^{2-}+16\text{H}^+\rightarrow2\text{Mn}^{2+}+5\text{s}+8\text{H}_2\text{O}$
For $5$ moles of $S$ the number of moles of $\text{KMnO}_4=2$
For $1$ moles of $S$ the number of moles of $\text{KMnO}_4=\frac{2}{5}$
For $5$ moles of $S$ the number of moles of $\text{KMnO}_4=2$
For $1$ moles of $S$ the number of moles of $\text{KMnO}_4=\frac{2}{5}$
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