MCQ
$C{H_2} = C{H_2}\xrightarrow{{B{r_2}/{H_2}O}}A,$ In the above reaction the compound $A$ is
  • Ethylene bromohydrin
  • B
    $1, 2-$ dibromo ethane
  • C
    Ethanol
  • D
    None of these

Answer

Correct option: A.
Ethylene bromohydrin
a
(a) $C{H_2} = C{H_2}\xrightarrow{{B{r_2},{H_2}O}}\mathop {\mathop {\mathop C\limits_| {H_2}}\limits_{Br\,\,\,\,} - \mathop {\mathop C\limits_| {H_2}}\limits_{OH\,\,\,\,} }\limits_{{\text{Ethylene bromohydrin}}} $
Hence compound $A$ is Ethylene bromohydrin.

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