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$C{H_3} - Br + \begin{array}{*{20}{c}}
  {\,\,\,\,\,C{H_3}} \\ 
  | \\ 
  {NaO - C - C{H_3}} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array} \to ?$

• ✓
  $\begin{array}{*{20}{c}}
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
    {\,\,\,\,\,\,\,\,\,|} \\ 
    {C{H_3} - O - C - C{H_3}} \\ 
    {\,\,\,\,\,\,\,\,\,|} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
  \end{array}$
• B
  $\begin{array}{*{20}{c}}
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
    {C{H_3} - C} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
  \end{array}$
• C
  $CH_2=CH_2$
• D
  $\begin{array}{*{20}{c}}
    {C{H_3} - O - CH - C{H_3}} \\ 
    {\,\,\,\,|} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
  \end{array}$