MCQ
$C{H_3} - CH = CH - CH(OH) - C{H_3}\mathop {\xrightarrow{{{\text{Jon's}}}}}\limits_{{\text{reagent}}} $ $X$,
Product $ X$ is
- A$C{H_3}C{H_2}C{H_2}CH(OH)C{H_3}$
- ✓$C{H_3}CH = CHCOC{H_3}$
- CBoth $(a)$ and $(b)$ are correct
- D$C{H_3}C{H_2}C{H_2}COC{H_3}$
