MCQ
$C{H_3} - CH = C{H_2} + HBr\xrightarrow{{}}..........,$ the product formed is
- A$C{H_3} - C{H_2} - C{H_2} - Br$
- ✓$C{H_3} - CHBr - C{H_3}$
- C$BrC{H_2} - CH = C{H_2}$
- D$C{H_2} = C = C{H_2}$
✓
Answer
Correct option: B.
$C{H_3} - CHBr - C{H_3}$
b
(b) $C{H_3} - CH = C{H_2} + HBr$ $\xrightarrow{Markownikkff \,rule}$ $\mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{Br\,\,} } - C{H_3}}\limits_{{\rm{2}} - {\rm{Bromopropane}}} $
(b) $C{H_3} - CH = C{H_2} + HBr$ $\xrightarrow{Markownikkff \,rule}$ $\mathop {C{H_3} - \mathop {CH}\limits_{\mathop {|\,\,\,\,\,}\limits_{Br\,\,} } - C{H_3}}\limits_{{\rm{2}} - {\rm{Bromopropane}}} $
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