MCQ
$CH_3 -CH=CH_2$ $\xrightarrow{{IBr}}$ Product $(A)$ is
- ✓

- B

- C

- D






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The above reaction is called
( Given that : ${\left( {\Delta {H^o}_f} \right)_{{H_2}O(g)}} = - 56.0\,\,kcal/mol$ and it is independnet of temperature).......$ K$
$(i)\, N_2 + 2O_2 \to 2NO_2\,\,\, \Delta H = 67.9\,kJ$
$(ii)\, N_2 + 2O_2 \to N_2O_4\,\,\, \Delta H = 9.3\,kJ$
......$kJ$