MCQ
$C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - C{H_2} - COO{C_2}{H_5}\mathop {\xrightarrow{{NaOH}}}\limits_{{H_2}O} A,$ product $‘A’$ in the reaction is
- A$C{H_3}COOH$
- B${C_2}{H_5}OH$
- C$C{H_3}COC{H_3}$
- ✓$(b)$ and $(c)$ both
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Assertion $A$ :$[6]$ Annulene.$[8]$ Annulene and cis - $[10]$ Annulene, are respectively aromatic, not-aromatic and aromatic.
Reason $R$ : Planarity is one of the requirements of aromatic systems.
In the light of the above statements, choose the most appropriate answer from the options given below.

