MCQ
${(C{H_3})_2}C = \mathop {CH}\limits_{\mathop {|\,\,\,\,\,\,\,}\limits_{C{H_3}} } \mathop {\xrightarrow{{{\text{Catalyst}}}}}\limits_{{H_2}} $ Optical isomers
- A$2$
- B$4$
- ✓$0$
- D$3$
✓
Answer
Correct option: C.
$0$
c
(c) ${(C{H_3})_2}C = \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} \mathop {\xrightarrow{{{\text{Catalytic}}}}}\limits_{{\text{hydro}}\,{\text{genation}}} {(C{H_3})_2}CH - \mathop {\mathop {C{H_2}}\limits_{|\,\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} $
(c) ${(C{H_3})_2}C = \mathop {\mathop {CH}\limits_{|\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} \mathop {\xrightarrow{{{\text{Catalytic}}}}}\limits_{{\text{hydro}}\,{\text{genation}}} {(C{H_3})_2}CH - \mathop {\mathop {C{H_2}}\limits_{|\,\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} $
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