- ACatalytic hydrogenation.
- BTreatment with LiAlH4.
- CTreatment with pyridinium chlorochromate.
- DTreatment with KMnO4.
Explanation:
Alcohols are oxidized to aldehydes and finally to acids.
$\text{CH}_3\text{CH}_2\text{OH}\xrightarrow{[\text{O}]}\text{CH}_3\text{CHO}\xrightarrow{[\text{O}]}\text{CH}_3\text{COOH}$
Oxidations can be stopped at aldehyde stage by using puridinium chlorochromate (CrO3C5H5N.HCl)
$\text{CH}_3\text{CH}_2\text{OH}\xrightarrow{\text{PCC}}\text{CH}_3\text{CHO}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_2} = C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(I)} \rightleftharpoons $
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C{H_2} - C - C{H_3}}
\end{array}}\limits_{(II)} \rightleftharpoons $
$\mathop {\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C = CH - C - C{H_3}}
\end{array}}\limits_{(III)} $

