- ABenedict's test
- ✓Iodoform test
- CTollen's reagent test
- DFehling's solution test
Febling-solution and Benedict solution. These reagents cannot be used to distinguish them
$C H_{3} C H O$ reacts with $N a O H$ and $I_{2}$ to form yellow crystalline iodoform while $C_{6} H_{5} C H_{2} C H O$
does not react with it. $\mathrm{CH}_{3} \mathrm{CHO}+3 \mathrm{I}_{2}+4 \mathrm{NaOH} \longrightarrow $$\mathrm{CHI}_{3}$ (Yellow crystalline ppt) $ +3 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}$
$C_{6} H_{5} C H_{2} C H O+3 I_{2}+4 N a O H \rightarrow N$ oreaction
$\therefore$ lodoform test can be used to distinguish between $C H_{3} C H O$ and $C_{6} H_{5} C H_{2} C H O$
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Statement $(I)$ : $\mathrm{SiO}_2$ and $\mathrm{GeO}_2$ are acidic while $\mathrm{SnO}$ and $\mathrm{PbO}$ are amphoteric in nature.
Statement $(II)$ : Allotropic forms of carbon are due to property of catenation and $\mathrm{p} \pi-\mathrm{d} \pi$ bond formation.
In the light of the above statements, choose the most appropriate answer from the options given below:
$A\left( s \right) \rightleftharpoons B\left( g \right) + C\left( g \right);{K_{{p_1}}} = x\,at{m^2}$
$D\left( s \right) \rightleftharpoons C\left( g \right) + E\left( g \right);{K_{{p_2}}} = y\,at{m^2}$
The total pressure when both the solids dissociate simultaneously is

[Assume steam to be an ideal gas. Given $A _{ vap } H ^{\ominus}$ for water at $373 \,K$ and $1\, bar$ is $41.1 \,kJ\, mol ^{-1} ; R =$ 8.31 $J\,K ^{-1} \,mol ^{-1}$ ]