MCQ
$CH_3CN$ $\xrightarrow{{Na + {C_2}{H_5}OH}}x$ The compound $x$ is
- A$CH_3CONH_2$
- ✓$CH_3CH_2NH_2$
- C$C_2H_6$
- D$CH_3NH-CH_3$
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(Figure) $\xrightarrow[FeB{{r}_{3}}]{B{{r}_{2}}}B\xrightarrow{Sn\,/\,HCl}C$ $\xrightarrow[HCl]{NaN{{O}_{2}}}D\xrightarrow[HBr]{CuBr}E$