MCQ
$C{H_3}N{O_2}\xrightarrow{{Sn + HCl}}C{H_3}X,$ the ‘$X$’ contain
- ✓$ - N{H_2}$
- B$ - \,COOH$
- C$ - \,CHO$
- D${(C{H_3}CO)_2}O$
✓
Answer
Correct option: A.
$ - N{H_2}$
a
(a)$C{H_3}N{O_2} + 6H\mathop {\xrightarrow{{Sn}}}\limits_{HCl} C{H_3}N{H_2} + 2{H_2}O$
(a)$C{H_3}N{O_2} + 6H\mathop {\xrightarrow{{Sn}}}\limits_{HCl} C{H_3}N{H_2} + 2{H_2}O$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The formula for lithium iodotris(trifluorophosphine)nickelate(0) is:
Which of the following compound evolve $2\ mole$ of $CO_2$ on gentle heating :
→The anion of acetylacetone $(acac)$ forms $Co\, (acac)_3$ chelate with $Co^{3+}.$ The rings of the chelate are
→In the diazotisation of aniline with sodium nitrite and hydrochloric acid, an excess of hydrochloric acid is used primarily to
Gun-cotton is obtained when conc. nitric acid reacts with
$C{H_3}C{H_2}OH\xrightarrow{{\operatorname{Re} dP + {I_2}}}\left( A \right)\xrightarrow[{Ether}]{{Mg}}\left( B \right)\xrightarrow{{HCHO}}\left( C \right)\xrightarrow{{{H_2}O}}\left( D \right)$
→The compound $(D)$ is
Product will be
Acetaldehyde reacts with $C{l_2}$ (in excess) to give
→$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,\,} \\
{\,\,N{H_2}}
\end{array}$ ${\xrightarrow{{HN{O_2}}}A}$ ${\xrightarrow{{oxidation}}B}$ ${\xrightarrow[{(ii){\kern 1pt} {H_2}O}]{{(i)C{H_3}MgI}}C}$
→{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,\,} \\
{\,\,N{H_2}}
\end{array}$ ${\xrightarrow{{HN{O_2}}}A}$ ${\xrightarrow{{oxidation}}B}$ ${\xrightarrow[{(ii){\kern 1pt} {H_2}O}]{{(i)C{H_3}MgI}}C}$
$C$ is
Which of the following is not hydrolysed