Question
Check if the relation given by the equation represents $y$ as function of $x$.

$x+y^2=9$

Answer

$\mathrm{x}+\mathrm{y}^2=9$
$\therefore \mathrm{y}^2=9-\mathrm{x}$
$\therefore \mathrm{y}= \pm \sqrt{9-x}$
$\therefore$ For one value of $\mathrm{x}$, there are two values of $\mathrm{y}$.
$\therefore \mathrm{y}$ is not a function of $\mathrm{x}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free