Question
Check the commutativity and associativity of the following binary operations:
$'⊙'$ on $Q$ defined by $a ⊙ b = a^2 + b^2$  for all $a, b \in Q.$

Answer

Commutativity: Let $\text{a, b}\in\text{Q}$ then,
$a ⊙ b = a^2 + b^2 = b^2 + a^2 = b ⊙ a$
Therefore, $a ⊙ b = b ⊙ a$, $\forall\ \text{a, b}\in\text{Q}$
Thus, $⊙$ is commuatative on $Q.$
Associativity: Let $\text{a, b, c}\in\text{Q.}$
$a ⊙ (b ⊙ c) = a ⊙ (b^2 + c^2) $
$= ab2 + (b^2 + c^2)^2 = ab^2 + b^4 + c^4 + 2b^2c^2 (a ⊙ b) ⊙ c $
$= (a^2 + b^2) ⊙ c = (a^2 + b^2)^2 + c^2 $
$=a^4 + b^4 + 2a^2b^2 + c^2$​​​​​​​ 
Therefore,$\text{a}\odot\text{b}\odot\text{c}\neq\text{a}\odot\text{b}\odot\text{c}$
Thus, $⊙$ is not associative on $Q.$

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