Question
Check whether the square of the following is rational or irrational:$3 + \sqrt{2}$
✓
Answer
$(3+\sqrt{2})^2 $
$=(3)^2+(\sqrt{2})^2+2 \times 3 \times \sqrt{2} $
$ =9+2+6 \sqrt{2} $
$ =11+6 \sqrt{2},$
which is irrational.
$=(3)^2+(\sqrt{2})^2+2 \times 3 \times \sqrt{2} $
$ =9+2+6 \sqrt{2} $
$ =11+6 \sqrt{2},$
which is irrational.
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