MCQ
Chirality of carbon compound is because of its
- ✓Tetrahedral nature of carbon
- BMonovalent nature of carbon
- CDivalent nature of carbon
- DTrivalent nature of carbon
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$(A)$ $NO _3^{-}$ $(B)$ $Cl ^{-}$ $(C)$ $SCN ^{-}$ $(D)$ $CN ^{-}$

$(R= 8.314\,\,JK^{-1}\,\,mol^{-1};\,\,ln\,2 = 0.693;\,\,ln\,3 = 1.098)$
$R - C \equiv N\xrightarrow[{(2)\,{H_2}O}]{{(1)\,AlH\,{{(i - Bu)}_2}}}$ ?
${C_2}{H_5}OH + SOC{l_2}\xrightarrow{{{\text{Pyridine}}}}{C_2}{H_5}Cl + S{O_2} + HCl$