- A$C{H_3} - CH = C{h_2}$
- B$C{H_2} = C{H_2}$
- C$CH \equiv CH$
- ✓All of the above
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Statement $I$ : Sulphanilic acid gives esterification test for carboxyl group.
Statement $II$ : Sulphanilic acid gives red colour in Lassigne's test for extra element detection.
In the light of the above statements, choose the most appropriate answer from the options given below :

The product in above reaction is
$\begin{array}{*{20}{c}} {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {( \pm )\,\,C{H_3} - C{H_2} - CH - C{H_3}} \end{array}$ $\xrightarrow[\Delta ]{{{H_3}P{O_4}}}P\,\xrightarrow[{Ni}]{{{D_2}}}Q$
$C{{H}_{3}}CN+2H\underset{\text{Ether}}{\mathop{\xrightarrow{HCl}}}\,X\underset{{{H}_{2}}O}{\mathop{\xrightarrow{\text{Boiling}}}}\,Y;$ the term $Y$ is: