MCQ
Chlorine can remove
  • $Br$ from $NaBr$ solution
  • B
    $F$ from $NaF$ solution
  • C
    $Cl$ from $NaCl$ solution
  • D
    $F$ from $Ca{F_2}$ solution

Answer

Correct option: A.
$Br$ from $NaBr$ solution
a
(a) $C{l_2} + 2NaBr\, \to \,2NaCl + B{r_2}$

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Similar questions

Match List $I$ with List $II$

List $-I$

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  List $-II$ (Electronic Configuration)  
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$C.$ $Br$ $III.$ $[\mathrm{He}] 2 \mathrm{~s}^2 2 \mathrm{p}^3$
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