- ✓$Br$ from $NaBr$ solution
- B$F$ from $NaF$ solution
- C$Cl$ from $NaCl$ solution
- D$F$ from $Ca{F_2}$ solution
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$\text{CH}_3\text{CH}_2-\text{CH}_2-\text{OH}$
$\text{CH}_3\text{CH}_2-\text{CH}-\text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\\text{CH}_3\text{CH}_2-\text{C}-\text{OH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Statement $I:$ In $Cl _{2}$ molecule the covalent radius is double of the atomic radius of chlorine.
Statement $II:$ Radius of anionic species is always greater than their parent atomic radius.
Choose the most appropriate answer from options given below :