MCQ
Chloropicrin is obtained by the reaction of
- ✓steam on carbon tetrachloride
- Bnitric acid on chlorobenzene
- Cchlorine on picric acid
- Dnitric acid on chloroform
Compound $Y$ must give iodoform test. Further since $Y$ is obtained by the oxidation of $X$ which must be an alcohol $(CH_3CH_2OH)$ and thus $Y$ is $CH_3CHO$
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$[Figure]$ $\xrightarrow{{{H^ + }/H{g^{2 + }}}}A$
the product '$ A'$ is
$Cu^+ /Cu = + 0.52\, V$,
$Fe^{3+} /Fe^{2+} = +0.7 7\, V$,
$\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, = + 0.54\,V,$
$Ag^+ /Ag = + 0.88\,V$.
Based on the above potentials, strongest oxidizing agent will be

$(i)$ $Xe{O_3}$ $(ii)$ $XeO{F_4}$ $(iii)$ $Xe{F_6}$
Those having same number of lone pairs on Xe are
What is $A$