Cholrine gas is produced from $\text{HCI}$ by the addition of:
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$\ce{KMnO_4}$ being strong oxidising agent will oxidise $CI^{− }$ ion present in $\ce{HCl}$ to form chlorine gas.
$\ce{2KMnO_{4 }+ 16HCl \rightarrow 2KCl + 2MnCl_{2 }+ 8H_2O + 5Cl_{2}}$
$\ce{2KMnO_{4 }+ 16HCl \rightarrow 2KCl + 2MnCl_{2 }+ 8H_2O + 5Cl_{2}}$
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