MCQ
Choose the correct answer. A thermodynamic state function is a quantity:
- AUsed to determine heat changes.
- BWhose value is independent of path.
- CUsed to determine pressure volume work.
- DWhose value depends on temperature only.
✓
Answer
- Whose value is independent of path.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The electrons are filled in various sub levels according to the order of their energies, is known as:
The absolute configuration of
Which of the following pairs show reverse properties on moving along a period from left to right and from top to bottom in a group?
The dissociation constant of a weak acid is $1 \times 10^{-4}.$ In order to prepare a buffer solution with a $pH = 5,$ the $[Salt]/[Acid]$ ratio should be
→Alkene $(A)$ will be
→$\mathop A\limits_{(alkene)} \xrightarrow[{{H_2}O}]{{RC{O_3}H}}$ Racemic mixture
$\mathop A\limits_{(alkene)} \xrightarrow{{Cold\,dil.KMn{O_4}}}$ Meso-compound
$X$ is
→Those elements impart colour to the flame on heating in it, the atoms of which require low energy for the ionisation (i.e., absorb energy in the visible region of spectrum). The elements of which of the following groups will impart colour to the flame?
Calculate $\Delta H_f^o$ for $UBr_4$ from the $\Delta G^o$ of reaction and the $S^o$ values :- $U(s) + 2Br_2(\ell ) \to UBr_4(s);\,\,$ $\,\,\Delta G^o =\,-\,788.6\,\,kJ;$
$S^o (J/K-mol)\,\, 50.3, 152.3, 242.6$ .....$kJ/mol$
→$S^o (J/K-mol)\,\, 50.3, 152.3, 242.6$ .....$kJ/mol$
A $10\,g$ effervescent tablet containing sodium bicarbonate and oxalic acid releases $0.25\,ml$ of $CO_2$ at $T = 298.15\,K$ and $p = 1\,bar$. If molar volume of $CO_2$ is $25.0\,L$ under such condition, what is the percentage of sodium bicarbonate in each tablet? [Molar mass of $NaHCO_3 = 84\,g\,mol^{-1}$ ]
→In the balanced chemical reaction,$IO_3^ - + a\;{I^ - } + b\;{H^ + } \to c\;{H_2}O + d\;{I_2}$ $a, b, c$ and $d $ respectively correspond to
→