MCQ
Choose the correct answer from the given four options.
If $\cos9\alpha=\sin\alpha\text{ and }9\alpha<90^\circ,$ then the value of $\tan5\alpha$ is:
  • A
    $\frac{1}{\sqrt{3}}$
  • B
    $\frac{\sqrt{3}}{1}$
  • $1$
  • D
    $0$

Answer

Correct option: C.
$1$
$\sin(90^\circ-9\alpha)=\sin\alpha$ $[\because\cos\text{A}=\sin(90^\circ-\text{A})]$
$\Rightarrow\ \ 90^\circ-9\alpha=\alpha$
$\Rightarrow\ \ 10\alpha=90^\circ$
$\Rightarrow\ \ \alpha=9^\circ$
$\therefore\tan5\alpha=\tan(5\times9^\circ)=\tan45^\circ=1$
$[\because\tan45^\circ=1]$

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