MCQ
Choose the correct answer from the given four options.
Let F = 3x - 4y be the objective function.
Minimum value of F is:
Let F = 3x - 4y be the objective function.
Minimum value of F is:
- A0.
- ✓-16.
- C12.
- DDoes not exist.
the feasible region as show in the figure, has objective function F= 3x - 4y
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Corner points
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Corresponding value of z = 3x - 4y
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(0, 0)
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0
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(12, 6)
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12 (masimum)
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(0, 4)
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-16 (miminum)
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$\int\limits_{ - \,1}^x {\,\left( {8{t^2} + \frac{{28}}{3}t + 4} \right)\,dt} $ $=$ $\frac{{\left( {{\textstyle{3 \over 2}}} \right)x + 1}}{{{{\log }_{(x + 1)}}\sqrt {x + 1} }}$ , is