MCQ
Choose the correct answer from the given four options. Let $f : R \rightarrow R$ be defined by $\text{f}(\text{x})=\begin{cases}2\text{x}:\text{x}>3\\\text{x}^2:1<\text{x}\leq3\\3\text{x}:\text{x}\leq1\end{cases}$ Then $f(-1) + f(2) + f(4)$ is:
  • $9$
  • B
    $14$
  • C
    $5$
  • D
    none of these.

Answer

Correct option: A.
$9$
We are given that, $\text{f}(\text{x})=\begin{cases}2\text{x}:\text{x}>3\\\text{x}^2:1<\text{x}\leq3\\3\text{x}:\text{x}\leq1\end{cases}$
Now, $f(-1) + f(2) + f(4)$
$ = 3(-1) + (2)^2 + 2 \times 4$
$= -3 + 4 + 8$
$= 9$

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