MCQ
Choose the correct answer from the given four options : In $\angle\text{BAC}=90^\circ$ and $\text{ AD}\perp\text{BC}.$ Then, Traingles


- A$ \mathrm{BD} \times \mathrm{CD}=\mathrm{BC}^2 $
- B$ \mathrm{AB} \times \mathrm{AC}=\mathrm{BC}^2 $
- ✓$ \mathrm{BD} \times \mathrm{CD}=\mathrm{AD}^2 $
- D$ \mathrm{AB} \times \mathrm{AC}=\mathrm{AD}^2 $
