MCQ
Choose the correct answer from the given four options: $\text{In }\angle\text{BAC}=90^\circ\text{ and}\text{ AD}\perp\text{BC}.\text{Then,}$
Traingles
Traingles- A$B D \times C D=B C^2$
- B$A B \times A C=B C^2$
- ✓$B D \times C D=A D^2$
- D$A B \times A C=A D^2$
