MCQ
Choose the correct answer from the given four options. The feasible solution for a $\text{LPP}$ is shown in. Let $Z = 3x - 4y$ be the objective function. Maximum of $Z$ occurs at :


- ✓$(5, 0)$
- B$(6, 5)$
- C$(6, 8)$
- D$(4, 10)$

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Corner points
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Corresponding value of $Z = 3x - 4y$
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$(0, 0)$
$(5, 0)$
$(6, 5)$
$(6, 8)$
$(4, 10)$
$(0, 8)$
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$0$
$15 ($Maxmimum)
$-2$
$-14$
$-28$
$-32$
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Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\left[\begin{array}{cc}
2 a+b & a-2 b \\
5 c-d & 4 c+3 d
\end{array}\right]=\left[\begin{array}{cc}
4 & -3 \\
11 & 24
\end{array}\right]$
$\frac{d y}{d x}=1+x e^{y-x},-\sqrt{2}\,<\,x\,<\,\sqrt{2}, y (0)=0$ then, the minimum value of $y(x)$ , $\mathrm{x} \in(-\sqrt{2}, \sqrt{2})$ is equal to: