MCQ
Choose the correct answer from the given four options.
The locus represented by xy + yz = 0 is:
  • A
    A pair of perpendicular lines.
  • B
    A pair of parallel lines.
  • C
    A pair of parallel planes.
  • A pair of perpendicular planes.

Answer

Correct option: D.
A pair of perpendicular planes.
We have, xy + yz = 0
⇒ xy = -yz
So, a pair of perpendicular planes.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Odds $8$ to $5$ against a person who is $40$ years old living till he is $70$ and $4$ to $3$ against another person now $50$ till he will be living $80$. Probability that one of them will be alive next $30$ years
If a line makes an angle of $45^\circ $ with the positive directions of each of $x-$ axis and $y-$ axis, then the angle that the line makes with the positive direction of the $z-$axis is .............. $^\circ $
The matrix $\begin{bmatrix} 5 & 10 & 3 \\ -2 & -4 & 6 \\ -1 & -2 & \text{b} \end{bmatrix}$ is a singular matrix, if the value of $b$ is:
The function $f: R \rightarrow R$ defined by $f(x)=6^x+6^{|x|}$ is
The acute angle between the line joining the points $(2,1,-3), (-3,1,7)$ and a line parallel to $\frac{{x - 1}}{3} = $ $\frac{y}{4} = \frac{{z + 3}}{5}$ through the point $(-1, 0, 4)$ is
In a triangle $PQR$, let $\overrightarrow{ a }=\overline{ QR }, \overrightarrow{ b }=\overrightarrow{ RP }$ and $\overrightarrow{ c }=\overline{ PQ }$. If $|\vec{a}|=3,|\vec{b}|=4$ and $\frac{\vec{a} \cdot(\vec{c}-\vec{b})}{\overrightarrow{ c } \cdot(\vec{a}-\vec{b})}=\frac{|\vec{a}|}{|\vec{a}|+|\vec{b}|}$, then the value of $|\vec{a} \times \vec{b}|^2$ is. . . . . . . 
If $f(x) = \left\{ \begin{array}{l}\frac{{\sin 2x}}{{5x}},{\rm{when\,\,}}\,x \ne 0\\\,\,\,\,\,\,\,\,\,\,\,\,k,{\rm{when \,\,}}x = 0\end{array} \right.$ is continuous at $x = 0$, then the value of  $ k $ will be
The degree of the differntial equation $\Big(\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}\Big)^{2}=\Big(\frac{\text{dy}}{\text{dx}}\Big)=\text{y}^{3}$ is:
If the solution $y(x)$ of the given differential equation $\left(e^y+1\right) \cos x d x+e^y \sin x d y=0$ passes through the point $\left(\frac{\pi}{2}, 0\right)$, then the value of $e^{y\left(\frac{\pi}{6}\right)}$ is equal to ...........
If $\text{A}=\begin{bmatrix} 2 & -1 \\ 3 & -2 \end{bmatrix},$ then $A^n=$