Choose the correct answer from the given four options. The vector… - Vidyadip

Question

Choose the correct answer from the given four options.
The vector having initial and terminal points as (2, 5, 0) and (–3, 7, 4), respectively is:

$-\hat{\text{i}}+12\hat{\text{j}}+4\hat{\text{k}}$
$-5\hat{\text{i}}+2\hat{\text{j}}-4\hat{\text{k}}$
$-5\hat{\text{i}}+12\hat{\text{j}}+4\hat{\text{k}}$
$\hat{\text{i}}+\hat{\text{j}}+\hat{\text{k}}$

✓

Answer

$-5\hat{\text{i}}+2\hat{\text{j}}+4\hat{\text{k}}$

Solution:

Given points are (2, 5, 0) and (–3, 7, 4).

Thus, the required vector $=(-3-2)\hat{\text{i}}+(7-5)\hat{\text{j}}+(4-0)\hat{\text{k}}$

$=-5\hat{\text{i}}+2\hat{\text{j}}+4\hat{\text{k}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from VECTOR ALGEBRA→VECTOR ALGEBRA — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

if x lies in the interval [0, 1], then the least value of x² + x + 1 is :

$3$
$\frac{3}{4}$
$1$
none of these.

Let $A=\left[a_{i j}\right]$ be a real matrix of order $3 \times 3$, such that $a_{i 1}+a_{i 2}+a_{i 3}=1$, for $i=1,2,3$. Then, the sum of all the entries of the matrix $A^{3}$ is equal to:

The reflection of the point $(\text{a}, \beta, \gamma) $ in the xy-plane is:

$(\alpha,\beta,0)$
$(0,0,\gamma)$
$(-\alpha,-\beta,\gamma)$
$(\alpha,\beta,\gamma)$

If $\int_{ - 1}^4 {f(x)\,dx} = 4$ and $\int_2^4 {(3 - f(x))\,dx = 7,} $ then the value of $\int_2^{ - 1} {f(x)\,dx} $ is

The period of the function $f\left( x \right)$ = $\frac{x}{3} - \left[ {\frac{x}{3} - 5} \right] + \frac{x}{4} - \left[ {\frac{x}{4} - 5} \right] + \frac{x}{5} - \left[ {\frac{x}{5} - 5} \right]$ is (where $[.]$ is $G.I.F.$ )

If $ O $ be the circumcentre and $ O'$ be the orthocentre of the triangle $ABC$ , then $\overrightarrow {O'A} + \overrightarrow {O'B} + \overrightarrow {O'C} = $

If $\text{P(B)}=\frac{3}{5},\text{P}(\text{A}|\text{B})=\frac{1}{2}$ and $\text{P}(\text{A}\cup\text{B})=\frac{4}{5},$ then $\text{P}(\overline{\text{A}\cap\text{B}})+\text{P}(\overline{\text{A}}\cap\text{B})=$

If a unit vector lies in $yz-$ plane and makes angles of ${30^o}$ and ${60^o}$ with the positive $y-$ axis and $z-$ axis respectively, then its components along the co-ordinate axes will be

The inverse of $\left[ {\begin{array}{*{20}{c}}2&{ - 3}\\{ - 4}&2\end{array}} \right]$is

If $f (x) =$ $\int\limits_0^{\pi /2} \frac{{\ell \,n\,\,(1\,\, + \,\,x\,\,{{\sin }^2}\,\,\theta )}}{{{{\sin }^2}\,\,\theta }}$ $d\, \theta$ , $x \geq 0$ then :