MCQ
Choose the correct answer. If $– 3x + 17 < – 13,$ then:
  • $\text{x}\in(10, \infty)$
  • B
    $\text{x}\in[10, \infty)$
  • C
    $\text{x}\in(-\infty\text{j},10]$
  • D
    $\text{x}\in[-10, 10)$

Answer

Correct option: A.
$\text{x}\in(10, \infty)$
Given that $- 3x + 17 < - 13$
$\Rightarrow - 3x < - 17 - 13$
$\Rightarrow -3x < - 30$
$\Rightarrow 3x > 30$
$\Rightarrow x > 10$
$\Rightarrow\text{x}\in(10, \infty)$

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