MCQ
Choose the correct answer. If $e$ is the eccentricity of the ellipse $\frac{\text{x}^2}{\text{a}^2}+\frac{\text{y}^2}{\text{b}^2}=1(\text{a}<\text{b}),$ then:
- A$ b^2=a^2\left(1-e^2\right) $
- ✓$ a^2=b^2\left(1-e^2\right) $
- C$ a^2=b^2\left(e^2-1\right) $
- D$ b^2=a^2\left(e^2-1\right) $