MCQ
Choose the correct answer. If $\text{f}(\text{x})=\sqrt{\text{x}}+\frac{1}{\sqrt{\text{x}}}$ then $\frac{\text{dy}}{\text{dx}}$ at $x = 1$ is equal to:
- A$1$
- B$\frac{1}{2}$
- C$\frac{1}{\sqrt{2}}$
- ✓$0$
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