MCQ
Choose the correct answer.
$\lim\limits_{\text{x} \rightarrow0}\frac{\text{x}^{\text{m}}-1}{\text{x}^{\text{n}}-1}$ is equal to:
  • A
    $1$ 
  • B
    $\frac{\text{m}}{\text{n}}$ 
  • C
    $\frac{-\text{m}}{\text{n}}$ 
  • D
    $\text{m}^{2}\text{n}^{2}$ 

Answer

  1. $\frac{\text{m}}{\text{n}}$

Solution:

Given $\lim\limits_{\text{x} \rightarrow 1}\frac{\text{x}^{\text{m}}-1}{\text{x}^{\text{n}}-1}=\lim\limits_{\text{x} \rightarrow 1}\frac{\frac{\text{x}^{\text{m}-(1)^\text{m}}}{\text{x}-1}}{\frac{\text{x}^{\text{n}-(1)^{\text{n}}}}{\text{x}-1}}$ 

$=\frac{\text{m}(1)^{\text{m}-1}}{\text{n}(1)^{\text{n}-1}}=\frac{\text{m}}{\text{n}}$

$=\frac{\text{m}}{\text{n}}$

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