MCQ
Choose the correct answer. Standard deviations for first 10 natural numbers is:
  • A
    5.5
  • B
    3.87
  • C
    2.97
  • 2.87

Answer

Correct option: D.
2.87
We know that SD of first n natural numbers $\sqrt{\frac{\text{n}^2-1}{12}}$
Here, $\text{n}=10$
$\therefore\ \text{SD}=\sqrt{\frac{(10)^2-1}{12}}=\sqrt{\frac{99}{12}} $
$=\sqrt{8.25}=2.87$

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