MCQ
Choose the correct answer. The total number of 9 digit numbers which have all different digits is.
  • A
    10!
  • B
    9 !
  • 9 × 9!
  • D
    10×10!

Answer

Correct option: C.
9 × 9!
  1. 9 × 9!
Solution:
We have to form 9-digit number which has all different digit.
First digit from the left can be filled in 9 ways (excluding ' 0 ').
Now nine digits are left including ' O '.
So remaining eight places can be filled with these nine digits in ${ }^9 \mathrm{P}_5$ ways.
So, total number of numbers $=9 \times{ }^9 \mathrm{P}_8=9 \times 9!$

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