PERMUTATIONS AND COMBINATIONS — MATHS STD 11 Science — Question
Gujarat BoardEnglish MediumSTD 11 ScienceMATHSPERMUTATIONS AND COMBINATIONS1 Mark
MCQ
Choose the correct answer. The total number of 9 digit numbers which have all different digits is.
A
10!
B
9 !
✓
9 × 9!
D
10×10!
✓
Answer
Correct option: C.
9 × 9!
9 × 9!
Solution:
We have to form 9-digit number which has all different digit.
First digit from the left can be filled in 9 ways (excluding ' 0 ').
Now nine digits are left including ' O '.
So remaining eight places can be filled with these nine digits in ${ }^9 \mathrm{P}_5$ ways.
So, total number of numbers $=9 \times{ }^9 \mathrm{P}_8=9 \times 9!$
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