MCQ
Choose the correct answer.
The value of arg(x), when x < 0 is:
The value of arg(x), when x < 0 is:
- A$0$
- B$\frac{\pi}{2}$
- C$\pi$
- DNone of these
Solution:
Let z = -x + 0i and x < 0
$\therefore\ |\text{z}|=\sqrt{(-1)^2+(0)^2}=1,\text{ x}<0$
Since, the point (-x, 0) lies on the negative side of the real axis $(\because\text{x}<0)$
$\therefore$ Principle argument $(\text{z})=\pi$
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