MCQ
Choose the correct answer. The value of $\text{arg(x),}$ when $x < 0$ is:
  • A
    $0$
  • B
    $\frac{\pi}{2}$
  • $\pi$
  • D
    None of these

Answer

Correct option: C.
$\pi$
Let $z = -x + 0i$ and $x < 0$
$\therefore\ |\text{z}|=\sqrt{(-1)^2+(0)^2}=1,\text{ x}<0$
Since, the point $(-x, 0)$ lies on the negative side of the real axis $(\because\text{x}<0)$
$\therefore$ Principle argument $(\text{z})=\pi$

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