CBSE BoardEnglish MediumSTD 11 ScienceMathsComplex Numbers and Quadratic Equations1 Mark
MCQ
Choose the correct answer. The value of $\text{arg(x),}$ when $x < 0$ is:
A
$0$
B
$\frac{\pi}{2}$
✓
$\pi$
D
None of these
✓
Answer
Correct option: C.
$\pi$
Let $z = -x + 0i$ and $x < 0$
$\therefore\ |\text{z}|=\sqrt{(-1)^2+(0)^2}=1,\text{ x}<0$
Since, the point $(-x, 0)$ lies on the negative side of the real axis $(\because\text{x}<0)$
$\therefore$ Principle argument $(\text{z})=\pi$
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