MCQ
Choose the correct option:
- ATrue dip is not mathematically related to apparent dip.
- ✓True dip is less than apparent dip.
- CTrue dip is always greater than the apparent dip.
- DTrue dip is always equal to apparent dip.
✓
Answer
Correct option: B.
True dip is less than apparent dip.
b
If apparent dip circle is at an angle $\alpha$ with true dip circle then
If apparent dip circle is at an angle $\alpha$ with true dip circle then
True dip circle
$[Image]$
Apparent dip circle
$[Image]$
As $\cos \alpha\,<1$
Hence true $\operatorname{dip}(\phi)$ is less than apparent $\operatorname{dip}\left(\phi^{\prime}\right)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A coil of $200\, \Omega$ resistance and $1.0 \,H$ inductance is connected to an $ac$ source of frequency $200/2\pi \,Hz.$ Phase angle between potential and current will be.....$^o$
→At a given instant, say $t = 0,$ two radioactive substances $A$ and $B$ have equal activates. The ratio $\frac{{{R_B}}}{{{R_A}}}$ of their activities. The ratio $\frac{{{R_B}}}{{{R_A}}}$ of their activates after time $t$ itself decays with time $t$ as $e^{-3t}.$ If the half-life of $A$ is $ln2,$ the half-life of $B$ is
→In the figure, the ball $A$ is released from rest when the spring is at its natural (unstretched) length. For the block $B$ of mass $M$ to leave contact with the ground at some stage, the minimum mass of $A$ must be
→If the atmospheric pressure is $P_a$, then the pressure $P$ at depth $h$ below the surface of liquid of density $\rho $ open to the atmosphere is
→Expansion during heating
A cord of negligible mass is wound around the rim of a wheel supported by spokes with negligible mass. The mass of wheel is 10 kg and radius is 10 cm and it can freely rotate without any friction. Initially the wheel is at rest. If a steady pull of 20 N is applied on the cord, the angular velocity of the wheel, after the cord is unwound by 1 m , would be :
The potential barrier, in the depletion layer, is due to
${ }_{92} U^{235}$ nucleus absorbs a neutron and disintegrates into ${ }_{54} X e^{139} ,{ }_{38} Sr ^{94}$ and $X$. What will be the product $X$ ?
→When the light of frequency $2v_0$ (where $v_0$ is threshold frequency), is incident on a metal plate , the maximum velocity of electrons emitted is $v_1$. When the frequency of the incident radiation is increased to $5v_0,$ the maximum velocity of electrons emitted from the same plate is $v_2$. The ratio of $v_1$ to $v_2$ is
→In Young's double slit arrangement, slits are separated by a gap of $0.5\, mm ,$ and the screen is placed at a distance of $0.5\, m$ from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of $5890\, A^o$ is
→