MCQ
Choose the correct statement about two circles whose equations are given below

$x^{2}+y^{2}-10 x-10 y+41=0$

$x^{2}+y^{2}-22 x-10 y+137=0$

  • A
    circles have same centre
  • B
    circles have no meeting point
  • circles have only one meeting point
  • D
    circles have two meeting points

Answer

Correct option: C.
circles have only one meeting point
c
$x^{2}+y^{2}-10 x-10 y+41=0$

$A (5,5), R _{1}=3$

$x^{2}+y^{2}-22 x-10 y+137=0$

$B (11,5), R _{2}=3$

$AB =6= R _{1}+ R _{2}$

Touch each other externally

$\Rightarrow$ circles have only one meeting point.

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