MCQ
Chords $AD$ and $BC$ intersect each other at right angles at point $P. \angle\text{DAB}=35^\circ,$ then $\angle\text{ADC}$ is equal to:
- A$35^\circ$
- B$45^\circ $
- C$65^\circ $
- ✓$55^\circ$
✓
Answer
Correct option: D.
$55^\circ$
From triangle $APB, \angle\text{ABP}=180^\circ-90^\circ-35^\circ=55^\circ$
Thus, $\angle\text{ADC}=55^\circ\ (\angle\text{ABC}=\angle\text{ADC})$
Thus, $\angle\text{ADC}=55^\circ\ (\angle\text{ABC}=\angle\text{ADC})$
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