MCQ
Chromyl chloride test is for
- A$Cl^-$
- ✓$N{ O_3}^-$
- C$CrO_4^{2 - }$
- D$(A)$ and $(C)$
$NH _3+3 Cl _2 \rightarrow NCl _3+3 HCl$
$X$ is $NH _3$ and $Y$ is $NCl _3$.
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$(i)\, [Co(NH_3)_5(NO_2 )]Cl_2$ and $[Co(NH_3)_5(ONO) ]Cl_2$ .... (Linkage)
$(ii)\, [Cu (NH_3)_4 ] [PtCl_4]$ and $[Pt(NH_3)_4] [CuCl_4]$ .... (Coordination)
$(iii)\, [PtCl_2 (NH_3)_4] Br_2$ and $[PtBr_2(NH_3)_4]Cl_2$ .... (Ionization)
Select the correct answer using the codes given below
${\text{2PQ}} \rightleftharpoons {{\text{P}}_2}{\text{ + }}{{\text{Q}}_2}\,;\,\,\,\,{{\text{K}}_1}{\text{ = 2}}{\text{.5 }} \times \,{\text{1}}{{\text{0}}^5}\,$
${\text{PQ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,;\,\,\,\,{{\text{K}}_2}{\text{ = 5 }} \times \,{\text{1}}{{\text{0}}^{ - 3}}\,$
The value of equilibrium constant for reaction
$\frac{1}{2}{{\text{P}}_2}{\text{ + }}\frac{1}{2}{{\text{Q}}_2}{\text{ + }}\frac{1}{2}{R_2} \rightleftharpoons PQR\,$ is
Reason : The colour arises due to charge transfer.