MCQ
Circumference of the first orbit of hydrogen atom is given by the formula :
- A$\frac{22}{7} \alpha _0$
- B$\frac{\pi \alpha _0}{2}$
- ✓$\sqrt 4 \pi \alpha _0$
- D$\pi \alpha _0$
✓
Answer
Correct option: C.
$\sqrt 4 \pi \alpha _0$
c
Circumference $=2 \pi r$
Circumference $=2 \pi r$
We have,
$r =\frac{ h ^2 \times n ^2}{4 \pi^2 me ^2} \cdot \frac{1}{ Z ^2}$
Hydrogen atom with $Z =1$ and $n =1$ radius is given by,
$r=\frac{h^2}{4 \pi^2 m^2}=a_0$
Therefore,
Circumference $=2 \pi a _0=\sqrt{4} \pi a _0$
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