Question
$CO _2$ is non-polar while $SO _2$ is polar, why?
✓
Answer
In $CO _2$ and $SO _2$ both compounds have polar bond but the geometry of $CO _2$ is linear. Hence due to the moments of both its $C - O$ bonds being in opposite directions, their effect gets cancelled due to which its dipole moment is zero, hence $CO _2$ is non-polar whereas it is not in case of $SO _2$. This happens because the geometry is angular, hence its dipole moment is not zero. Hence it is polar.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The $K_{\text {sp }}$ of PbS is $4 \times 10^{-28}$. If $\left[ Pb ^{+2}\right]=4 \times$ $10^{-27}$ then what will be the minimum concentration of $S ^{-2}$ to precipitation PbS ?
→Calculate volume $CO _2$ gas at NTP obtained by complete combustion of 500 ml ethyne $\left( C _2 H _2\right)$.
→At 523 K temperature following reaction $PCl _5(g) \rightleftharpoons PCl _3(g)+ Cl _2(g)$ value of $K _{ p }$ is 2.35 atm then calculate value of $K_c \cdot\left(R=0.082 L\right.$ atm degree ${ }^{-1}$ $mol ^{-1}$.
→- What is the oxidation number of Fe in Fe3O4?
$\text{H}^++\text{MnO}_4^-+\text{Fe}^{2+}\xrightarrow{ \ \ \ \ \\ \ \ }\text{Fe}^{3+}+\text{Mn}^{2+}+\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{(Acidic medium)}$
- Balance the equation.
If the value of an equilibrium constant for a particular reaction is 1.6 × 1012, then at equilibrium, what will be present in the system?
Br2 + 2Cl- → Cl2 + 2Br-, will this reaction take place or not?
$\text{E}^0_\frac{\text{Br}_2}{\text{Br}^-}=+1.09\text{V}$
$\text{E}^0_\frac{\text{Cl}_2}{\text{Cl}^-}=+1.36\text{V}$
→$\text{E}^0_\frac{\text{Br}_2}{\text{Br}^-}=+1.09\text{V}$
$\text{E}^0_\frac{\text{Cl}_2}{\text{Cl}^-}=+1.36\text{V}$
What will be the pOH of $\frac{ M }{100} \quad H _2 SO _4$ solution ?
→
Use molecular orbital theory to explain why the $Be _2$ molecule does not exist.
→Why is ammonia termed as a base though it does not contain OH- ions?