MCQ
$CO$ has same electrons as or the ion that is isoelectronic with $CO$ is
- A$N_2^ + $
- ✓$C{N^ - }$
- C$O_2^ + $
- D$O_2^ - $
$CO = 6 + 8 = 14$ and $C{N^ - } = 6 + 7 + 1 = 14$.
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$(A)$ Over all order of this reaction is one
$(B)$ Order of this reaction can't be determined
$(C)$ In region$-I$ and $III$, the reaction is of first and zero order respectively
$(D)$ In region$-II$, the reaction is of first order
$(E)$ In region$-II$, the order of reaction is in the range of $0.1$ to $0.9$.