MCQ
CO is isoelectronic with:
- ANO+
- BN2
- CSnCl2
- D
Explanation:
Number of electrons in CO =14
Number of electrons in NO+= 14
Number of electrons in N2 = 14
Number of electrons in SnCl2 = 84
Number of electrons in NO–2 = 24
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Assertion $(A)$ : Boron is unable to form $BF _{6}^{3-}$
Reason $(R)$ : Size of $B$ is very small.
In the light of the above statements, choose the correct answer from the options given below.

