MCQ
$CO + NaOH \to $
- ✓$HCOONa$
- B${C_2}{H_2}{O_4}$
- C$HCOOH$
- D$C{H_3}COOH$
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$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}CHC{H_2}C{H_2}N{H_2}}
\end{array}$ $\xrightarrow[{triethyla\min e}]{{ethyl\,formate\,\left( {1\,equiv} \right)}}$
$Compound\xrightarrow{{KMn{O_4}/{H^ \oplus }}}$
$(I)\,\,C{H_2} = CH - \mathop C\limits^ \oplus {H_2}$
$(II)\,\,C{H_3} - CH_2 - \mathop C\limits^ \oplus {H_2}$
$A + B \to C + D$
The enthalpy change and activation energy for the reverse reaction $C + D \to A + B$ are respectively